Light with a wavelength 3.00 *10^2 nm is absorbed by a certain metal... (SEE PIC

Question

Light with a wavelength 3.00 *10^2 nm is absorbed by a certain metal...

(SEE PICTURE. Need all parts including help with figures. My answers were wrong )

Light with a wavelength of 3.00 x102 nm is abosrbed by a certain metal, which then emits an electron Answer the three questions below, using three significant figures. Part A: How much energy (Ei) does each photon of the light carry? Number e V Part B: The maximum kinetic energy of the emitted electrons is found to be 1.60 eV. What is the value of the work function (for the metal? Number e V Part C: What is the name of this effect? O the deBroglie effect O the Compton effect O the Bragg effect O the positronic emission effect O the photoelectric effect O Actually, there is no special name for this effect.

Explanation / Answer

E = hc/lambda

h = plamck constant = 6.626 x 10^-34

c = speed of light = 3 x 10^8

E = 4.14125 eV

part b )

E = KE + phi

phi = E - KE = 2.54125 eV

part c )

this effect called photo electric effect

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