a.)Consult Interactive Solution 2.22 before beginning this problem. A car is tra
ID: 1513362 • Letter: A
Question
a.)Consult Interactive Solution 2.22 before beginning this problem. A car is traveling along a straight road at a velocity of +27.9 m/s when its engine cuts out. For the next 2.92 seconds, the car slows down, and its average acceleration is . For the next 3.79 seconds, the car slows down further, and its average acceleration is . The velocity of the car at the end of the 6.71-second period is +15.7 m/s. The ratio of the average acceleration values is = 1.71. Find the velocity of the car at the end of the initial 2.92-second interval.
b.)In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 5.98 m/s in 2.79 s. Assuming that the player accelerates uniformly, determine the distance he runs.
Explanation / Answer
from equation of mortion
v = u + at
15.7 = 27.9 + (a*6.71)
acceleration a = -1.82 m/s^2
++++++++++++++++
after 2.92 s
speed v = 27.9 - (1.82*2.92)
v = 22.6 m/s
++++++++
(b)
v = u + at
5.98 = 0 + a*2.79
a = 2.143 m/s^2
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