The height of a tower is measured by attaching a simple pendulum to its ceiling,
ID: 1513407 • Letter: T
Question
The height of a tower is measured by attaching a simple pendulum to its ceiling, whose length is barely enough to stay off the floor. The pendulum is let go from a small angle at a height of 0.2 m above the floor, and takes 15 s to return to the same location it started from.
a.) How tall is the tower?
_________ m
b.) How fast is the mass travelling at its lowest point?
__________ m/s
c.) What angle did the pendulum string make with the vertical when it was released?
_________ degrees
(Does this seem "small" to you?)
Explanation / Answer
the period appears to be 15 s
T = 2pi sqrt( L / g )
15 = 2pi sqrt ( L / 9.81)
(15/2pi)^2 = L / 9.81
L = 55.91 m
conservation of energy
PE at start = KE at bottom
it's all GPE at the release point and all KE at the bottom of the swing)
m*g*h = 1/2*m*v^2
v = sqrt( 2*g*h )
v = 1.98m/s
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