As shown in the figure, two long, straight current-carrying wires (1 and 2) are

Question

As shown in the figure, two long, straight current-carrying wires (1 and 2) are attached at right angles to a board by wire brackets. The current in wire 1 is 17.9 A in the negative y direction and the current in wire 2 is 5.00 A in the positive x direction. The points A and B are a distance,t=0.200m from both wires. How does the magnitude of the net magnetic field at point A compare to the magnitude of the net magnetic field at point B? Determine the magnitude of the net magnetic field at points A and B. If the brackets holding wire 2 are removed, what will happen to wire 2?

Explanation / Answer

I1 = 17.9 A
I2 = 5.0 A
r = 0.2 m

Magnetic field due to current carrying wire is given by, B = (uo*I)/(2*pi*r)
Let magnetic Field due to wire 1 & 2 is B1 & B2 respectively.

At point A,
Bnet = B1 - B2
Bnet = (uo*I1)/(2*pi*r) -  (uo*I2)/(2*pi*r)
Bnet = (2*10^-7*)/(0.2) * [17.9 - 5.0]
Bnet = 1.29 * 10^-5 T


At point B,
Bnet = B1 + B2
Bnet = (uo*I1)/(2*pi*r) + (uo*I2)/(2*pi*r)
Bnet = (2*10^-7*)/(0.2) * [17.9 + 5.0]
Bnet = 2.29 * 10^-5 T

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