ing 2018 two pure lines of plants, one with yellow petals and one the F1 was sel
ID: 151479 • Letter: I
Question
ing 2018 two pure lines of plants, one with yellow petals and one the F1 was selfed, the F2 generation had p 61 Yellow 182 Orange with red were Interbred. The F1 all had orange petals. sd the following phenotype s re interbred, The Fl all had orange petals. when 77 Red las Assuming this trait is controlled by a single locus with two alleles (Red and (orange plants are heterozygous) use the trait are randomly segregating. showing partial dominance xGoodness of Fit Test to investigate whether the alleles of the petal color Table of Critical Values for P-0.05 Degrees of 1 Freedomm Critical Values 3.84 5.99 7.82 9.49 11.07 12.5914.0715.51 2 33124 136.3 low 151.6 1 we uwill reect the hy pattes s hey crend randomiExplanation / Answer
Null hypothesis: The observed values are not deviating from the expected ratio i.e. 1:2:1.
Chisquare test:
Categories
Yellow
Oragne
Red
Total
Observed values (O)
61.00
182.00
77.00
320
Exptected Ratio (ER)
1
2
1
4
Exprected Values (E)
80
160
80
Deviation (O-E)
-19
22
-3
D^2
361
484
9
D^2/E
4.5125
3.025
0.1125
7.65
X^2
7.65
Degrees of freedom
3-1=2
Inference: As the calculated chisquare value i.e. 7.65 is greater than the table value i.e. 5.99 at 0.05 probability and 2 DF, the null hypothesis is rejected.
Categories
Yellow
Oragne
Red
Total
Observed values (O)
61.00
182.00
77.00
320
Exptected Ratio (ER)
1
2
1
4
Exprected Values (E)
80
160
80
Deviation (O-E)
-19
22
-3
D^2
361
484
9
D^2/E
4.5125
3.025
0.1125
7.65
X^2
7.65
Degrees of freedom
3-1=2
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