Same as problem\" 28 except instead of a mirror, it is a UlvtKGhN I lens, which

Question

Same as problem" 28 except instead of a mirror, it is a UlvtKGhN I lens, which has a focal length of 84 cm. An object is located SO cm in front of the lens. Where is the image distance? Calculate the image distance and also describe in a ray diagram. Same as problem" 28 except instead of a mirror, it is a UlvtKGhN I lens, which has a focal length of 84 cm. An object is located SO cm in front of the lens. Where is the image distance? Calculate the image distance and also describe in a ray diagram ray of light from earth's atmosphere strikes a frozen lake at 40 degrees. What are the angles of reflection and refraction? (index of refraction for ice is 1.309)

Explanation / Answer

30)
f = -84 cm
do = 50 cm
use:
1/f = 1/di + 1/do
-1/84 = 1/di + 1/50
di = -31.34 cm
Answer: 31.34 cm

31)
angle of reflection will be i = 40 degree
Let angle of refraction be r
use Snell's law:
n1*sin i = n2* sin r
1*sin 40 = 1.309*sin r
r = 29.4 degree

32)
critical angle, iC = asin (1/n2)
                                 = asin (1/1.309)
                                 = 49.8 degree
Polarising angle,iB = atan (n2)
                                       = atan (1.309)
                                       = 52.6 degree

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