Right answer gets high rating The figure at the right shows a small positive cha

Question

Right answer gets high ratingThe figure at the right shows a small positive charge some distance away from a larger positive charge. The smaller charge is currently a distance r1 away from the center of the larger charge, which is twice as far away as r2.

-On part C is it negative?

The figure at the right shows a small positive charge some distance away from a larger positive charge. The smaller charge is currently a distance r1 away from the center of the larger charge, which is twice as far away as r2. Answer the three questions below, using three significant digits. Part A: What happens to the potential energy and the force if the smaller charge is moved to r2? O O Both the force and the poential energy decrease. Both the force and the potential energy increase. ra The force increases, but the potential energy decreases The force decreases, but the potential energy increases O Neither the force nor the potential energy change. Neither the force nor the potential energy change Part B: Suppose that there is a (F2) when the charge is moved to r2? force of 0.0123 N when the smaller charge is at r1. What is the value of the force Number Part C: Suppose that the potential energy is 5.77 x103 J when the smaller charge is at r. What is the vlaue of the potential energy (U2) when the charge is moved to r2? Number

Explanation / Answer

r1 = 2*r2
(a)
Electrostatic Force is given by
F = k*q*Q/r^2
Potential Energy is given by,
U = k*q*Q/r

As r would decreas,
Both Force & Potential Energy wound increase.

(b)
Force at r1,
F = k*q*Q/r1^2

Force at r2,
F' = k*q*Q/r2^2
F' = F*r1^2 / r2^2
F' = F * (2*r2)^2/ r2^2
F' = 4*F
F' = 4*0.0123 N
F' = 0.0492 N

(c)
Potential Energy at r1,
U = k*q*Q/r1

Potential Energy at r2,
U' = k*q*Q/r2
U' = U*r1/r2
U' = U*2
U' = 2 * 5.77 * 10^-3 J
U' = 1.15 * 10^-2 J

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