In the figure shown, a physical pendulum consists of a uniform solid disk (of ra

Question

In the figure shown, a physical pendulum consists of a uniform solid disk (of radius R = 2.22 cm and mass M = 0.324 kg) supported in a vertical plane by a pivot located a distance d = 1.56 cm from the centre of the disk. The disk is displaced by a small angle and released. Using the parallel axis theorem, find the rotational inertia of the disk about the pivot point. (The rotational inertia of a disk its centre of mass is I_com =1/2 MR^2.) What is the period of the resulting simple harmonic motion?

Explanation / Answer

a) I = 0.5*mr^2 + md^2 = 0.00015868872 kgm^2
b) T = 2*pisqroot(I/mgl) = 0.355455

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