In a photoelectric-effect experiment, the maximum kinetic energy of electrons is

Question

In a photoelectric-effect experiment, the maximum kinetic energy of electrons is 2.8 eV . When the wavelength of the light is increased by 50%, the maximum energy decreases to 1.2 eV .

Part A

What is the work function of the cathode?

Express your answer using two significant figures.

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Part B

What is the initial wavelength?

Express your answer using two significant figures.

In a photoelectric-effect experiment, the maximum kinetic energy of electrons is 2.8 eV . When the wavelength of the light is increased by 50%, the maximum energy decreases to 1.2 eV .

Part A

What is the work function of the cathode?

Express your answer using two significant figures.

E0 =   eV  

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Part B

What is the initial wavelength?

Express your answer using two significant figures.

=   nm  

Explanation / Answer

Work function of cathode is 2.8 eV

b)E = hc/wavelength = 1.2 ev

hc/2*wavelength = 1.2 ev

hc/ wavelength = 2.4 ev

wavelength = 6.6*10^-34*3*10^8/2.4*1.6*10^-19

wavelength = 5.156 *10^-7 m = 515.6 nm

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