A .5 m long straight wire carries a current at 1.25 A. An electron travels at 10
ID: 1517863 • Letter: A
Question
A .5 m long straight wire carries a current at 1.25 A. An electron travels at 10, 000 m/s parallel to the wire at point R, 20 cm from the entire what Is the magnetic field due to the wire at point R, which is 20 cm from the wire? What is the magnitude of the force exerted by this magnetic field on the electron? What is the direction of the magnetic force? What is the direction of the magnetic field due to the wire below? Choices: Into the page out of the page up, down, left and right. Write the answer in the blank space provided If the square loop is moving away from the current-carrying wire, what is the direction of the induced current in the wire? Choices: clockwise, counter-clockwise, neither. Write your answer beside the diagram A 60cm wire is mode into a square loop end placed into a constant magnetic field of magnitude 150T pointed through the loop Calculate the induced EMF (voltage) if the loop is suddenly pulled out of the magnetic field in 0.025s. Assume the loop it placed bock info the same magnetic field but this time, the square is mode into on equilateral Triangle in 4.56s. Calculate the induced EMF. An object is placed 15 cm in front of a convex mirror with a focal length of 30 cm. What is the modification and the image properties An object is located 20 cm from o diverging lens having a focal length of 32 cm Determine the magnification of the image and the image properties.Explanation / Answer
A) Induced emf = -Area*(dB/dt) = -0.15^2*(1.5 – 0)/0.025 = -1.35 V
B) Area of triangle = 0.5*0.20*0.1732 = 0.01732 m^2
Induced emf = -Area*(dB/dt) = -0.01732*(0 – 1.5)/4.56 = 5.7 mV
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