The thin glass shell shown in (Figure 1) has a spherical shape with a radius of
ID: 1518891 • Letter: T
Question
The thin glass shell shown in (Figure 1) has a spherical shape with a radius of curvature of 9.50 cm , and both of its surfaces can act as mirrors. A seed 3.30 mm high is placed 15.0 cm from the center of the mirror along the optic axis, as shown in the figure.
Part A
Calculate the location of the image of this seed.
Express your answer in centimeters to three significant figures.
Part B
Calculate the height of the image of this seed.
Express your answer in millimeters to three significant figures.
Part C
Suppose now that the shell is reversed. Find the location of the seed's image.
Express your answer in centimeters to three significant figures.
Part D
Find the height of the seed's image.
Express your answer in millimeters to three significant figures.
15.0 cmExplanation / Answer
R = 9.5
so f = R/2 = 9.5/2 =4.75
1/ v + 1/ u = 1/f
1/v +1/ -15 = 1/ -4.75
v= -6.95 image distance from mirror .
m = -v/u = --6.95 / -15 =-0.463333333
height of image = 3.30* 0.463333333 =1.52900 mm inverted real .
Part C
1/v +1/ -15 = 1/ 4.75
v= 3.60759 cm
PArt D
m = -v/u = - 3.60759/ -15 =0.240506
height of image = 3.30 * 0.240506 =0.7936698 mm virtual erected
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