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The thin glass shell shown in (Figure 1) has a spherical shape with a radius of

ID: 1518891 • Letter: T

Question

The thin glass shell shown in (Figure 1) has a spherical shape with a radius of curvature of 9.50 cm , and both of its surfaces can act as mirrors. A seed 3.30 mm high is placed 15.0 cm from the center of the mirror along the optic axis, as shown in the figure.

Part A

Calculate the location of the image of this seed.

Express your answer in centimeters to three significant figures.

Part B

Calculate the height of the image of this seed.

Express your answer in millimeters to three significant figures.

Part C

Suppose now that the shell is reversed. Find the location of the seed's image.

Express your answer in centimeters to three significant figures.

Part D

Find the height of the seed's image.

Express your answer in millimeters to three significant figures.

15.0 cm

Explanation / Answer

R = 9.5   

so f = R/2 = 9.5/2 =4.75

1/ v + 1/ u = 1/f

1/v +1/ -15 = 1/ -4.75

v= -6.95 image distance from mirror .

m = -v/u = --6.95 /  -15 =-0.463333333

height of image = 3.30* 0.463333333 =1.52900 mm inverted real .

Part C

1/v +1/ -15 = 1/ 4.75

v= 3.60759 cm

PArt D

m = -v/u = - 3.60759/ -15 =0.240506

height of image = 3.30 * 0.240506 =0.7936698 mm virtual erected

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