Chapter 25 Question 22 Part A A spaceship visits a star that is 4.5 light-years
ID: 1518984 • Letter: C
Question
Chapter 25 Question 22 Part A A spaceship visits a star that is 4.5 light-years from Earth, and the spaceship travels at one-half the speed of light for the entire trip. (a) How long did the trip take according to an observer on Earth? (b) How long did the trip take according to an observer on the spaceship? Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining SubmitMy AnswersGive Up Provide FeedbackContinue Introductory Physics II- 10Z1_79696 Help Close 13: Special Relativity THIS IS EXTRA ... Chapter 25 Question 22 « previous 19 of 22 next »
Explanation / Answer
star is at a distance of d = 4.5 light years = 4.5*365*24*60*60*3*10^8= 4.25736*10^13 km
as the spaceship moving with speed 1.5*10^8 m/s , time taken for the space ship to travel 4.5 ly is
observer on earth is t= d/v = 4.25736*10^16/1.5*10^8 = 283824000 s = 9 years
as observed by observer on space ship is T'= T sqrt(1- v^2/c^2) = 283824000(sqrt(1-0.5^2 c^2/c^2))
T'= 7.794 yrs
time delation takes place.
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