Answers 19=C 20=E Please explain!!! The following scenario will be the subject o

Question

Answers

19=C

20=E

Please explain!!!

The following scenario will be the subject of the next two questions. A 200 g, 20 cm long thin rod is initially at rest on an icy surface (frictionless surface). An incoming puck strikes the rod at one of its ends, as depicted in the figure below. The puck can be treated as a point particle that has a mass of 100 g, moving with a velocity of (-20 m/s) j before the collision and (-10 m/s) j after the collision. 2 seconds after the collision, how far has the rod's center of mass traveled? 0 m 5 m 10 m 20 m 30 m How many revolutions will the rod undergo in the 2 seconds after the collision? 6 revolutions 12 revolutions 24 revolutions 36 revolutions 48 revolutions

Explanation / Answer

19)

conserving linear momentum

100 ( -20 ) = 100(-10) + 200xv

v = -5 m/sec

distance travelled

d = vxt = 5x2 = 10 m

20)

,conserving angular momentum

0.1 x 20 xL/2 = 0.1x10 L/2 + 0.2L^2/12 w

substituting we get

0.5 = 0.2 wL/12

w = 150 rad/sec

theta = w xtime = 300 radians

theta = 300/2xpi rev = 47.746 rev = 48 rev

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