In an RL circuit, the time required for the current In the circuit to reach 63 2

Question

In an RL circuit, the time required for the current In the circuit to reach 63 2% of its final value is given by the time constant, tau. True False Write the equation for the emf associated with an RL circuit In addition, label each letter In the equation with one of the following terms change in time; inductance, emf, change In current. Write down the equation for the time constant of an RL circuit In addition label each letter in the equation with one of the following terms inductance, resistance time constant. Draw the circuit symbol for an inductor.

Explanation / Answer

I = (V/R) * ( 1 - e^-t/(tau))

After 1 tau, I = (V/R) * ( 1 - (1/e)) = 63% of I final.. So True.

V = Vr +Vl SO IR + L dI/dt = 0

dI/dt = change in current. V = EMF by battery . I f battery is not present V = 0

L = inductance. R = Resistance.

Time constant is (tau) . Tau = L/R for an LR circuit in series.

An inductor is represented by a symbol like helical spring.

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