An insect 1.2 mm tall is placed 0.9 mm beyond the focal point of the objective l

Question

An insect 1.2 mm tall is placed 0.9 mm beyond the focal point of the objective lens of a compound microscope. The objective lens has a focal length of 10 mm , the eyepiece a focal length of 23 mm .

Part A

Where is the image formed by the objective lens?

Give your answer as the distance from the image to the lens. Express your answer using two significant figures.

Part B

How tall is the image mentioned in part A?

Express your answer using two significant figures.

Part C

If you want to place the eyepiece so that the image it produces is at infinity, how far should this lens be from the image produced by the objective lens?

Express your answer using two significant figures.

Part D

Under the conditions of part C, find the overall magnification of the microscope.

Express your answer using two significant figures.

Explanation / Answer

1/ v -1/ u = 1/ f

1/ v -1/ -0.9 = 1/ 10

v= - 0.989 mm

partB )

m = v/u = - 0.989 / -0.9 =1.09888889

height of image = 1.2*1.09888889 = 1.31866667 mm .................answer

C )

this lens should be 23 mm away from image

D) 1.0988

m = v/u

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