Virgil rides a skateboard (combined mass 100 kg) at 4 m/s, and Jill rides a bicy

Question

Virgil rides a skateboard (combined mass 100 kg) at 4 m/s, and Jill rides a bicycle (combined mass 64 kg) at 5 m/s. Virgil has the greater kinetic energy. Jill has the greater kinetic energy. Virgil and Jill have equal kinetic energies. An object with a kinetic energy of 40 J is stopped in a distance of 0.01 m. The average force that Stops the Object is 40.000 N. 4.000 N. 400 N. 40 N. 0.4 N. A 3.0-kg cat runs to the left at 10 m/s and a 10 kg dog runs to the right at 4.0 m/s. The tot kinetic energy is -35 Joule. 0. -70 Joule. 146 Joule. 230 Joule. A child riding on a swing rises to a height 1.0 m above the lowest point. Another chi equal mass whose speed at the lowest point is twice as great will rise to a height which depends on the mass. to the same height. twice as high. four times as high.

Explanation / Answer

1) KEv = 1/2*mv*Vv^2 = 800 J

KEJ = 1/2*mj*Vj^2 = 800 J

Option C is correct

2) Force = E/x = 40/0.01 = 4000 N

Option B is correct

3) Total KE will be the sum of KE of dog and cat ie

= 0.5*3*10^2 + 0.5*10*4^2 = 230 J

4) Here KE = PE

Let H be the height of the second child get

1/2mv^2 = mgh ......(1)

1/2m(2v)^2 = mgH ......(2)

Divide (2) by (1)

H/h = 4

H = 4h = 4m

Hence option D is correct

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