HEEEEELP! I\'ve tried so many different answers for part A, but I keep going bac
ID: 1521780 • Letter: H
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HEEEEELP! I've tried so many different answers for part A, but I keep going back to 9.75 x 10^24 or 9.75 x 10^27 & neither one are correct! If someone can explain this, I'd greatly appreciate it.
2 https://session.masteringphysics.com/myct/item View?assignmentProblemID-63030456 ar Problem 16.21 How many helium atoms are in the cylinder? A 40.0 cm -diameter cylinder of helium gas is 40.0 cm long and at 10.0 °C. The pressure gauge reads 110 psi atoms Submit My Answers Give Up Incorrect; Try Again; 3 attempts remaining Part B What is the mass of the helium Submit My Answers Give Up Part C What is the helium number density? atoms/mExplanation / Answer
V = pi*0.2^2*0.4 = 0.05024 m^3
PV = nRT
758423*V = n*R*283.16
n = 16.1930 moles = 97.51444 *10^23 atoms
B. Mass = n*4 = 64.7721316 g
C. Number density = n/V = 1940.972216*10^23 atoms / m^3
D. Mass density = m/V = 1.289266 kg/m^3
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