A 5-kg box is sliding along a horizontal floor. Three horizontal forces act on t

Question

A 5-kg box is sliding along a horizontal floor. Three horizontal forces act on the box. Force F1 has a magnitude of 15 N and is directed rightward, force F2 has a magnitude of 15 N and is directed leftward, and force F3 has a magnitude of 5 N and is directed leftward. At t = 0 s, the velocity of the block is 5 m/s to the right. Let rightward be the positive direction.

Is the acceleration of the box positive, negative, or zero?

Positive Zero     Negative

What is the magnitude of the box's acceleration?
m/s2

What is the block's displacement from t = 0 s to t = 3 s?
m

Explanation / Answer

here,

mass , m = 5 kg

F1 = 15 N

F2 = - 15 N

F3 = - 5 N

the net force , F = F1 + F2 + F3

F = - 5 N

so accelration , a = net force /mass = - 5 /5 m/s^2

a = - 1 m/s^2

the accelration is negative

the magnitude of box accelration is 1 m/s^2

initial speed , u = 5 m/s

for t = 3 s

the block's displacement , s = u * t+ 0.5 * a * t^2

s = 5 * 3 + 0.5 * 1 * 3^2

s = 19.5 m

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