Two point charges are separated by 25.0 cm(see (Figure 1) ). Assume that q 1 = -
ID: 1523127 • Letter: T
Question
Two point charges are separated by 25.0 cm(see (Figure 1) ). Assume that q1 = -5.50 nC and q2= -10.0 nC .
Part A
Find the net electric field these charges produce at point A.
Express your answer in newtons per coulomb to three significant figures.
Part B
Find the net electric field these charges produce at point B.
Express your answer in newtons per coulomb to three significant figures.
Part C
What would be the magnitude of the electric force this combination of charges would produce on a proton at A?
Express your answer in newtons to three significant figures.
Part D
What would be the direction of the electric force this combination of charges would produce on a proton at A?
What would be the direction of the electric force this combination of charges would produce on a proton at ?
gi 10.0 cm 10.0 cm. 25.0 cmExplanation / Answer
A)Field due to q1 is E1 = k*q1/x1^2 = (9*10^9*5.5*10^-9)/0.15^2 = 2200 N/C towards q1 from A
Field due to q2 is E2 = k*q2/x2^2 = (9*10^9*10*10^-9)/(0.1^2) = 9000 N/C towards q2 form A
net electric field is E = E1-E2 = 2200-9000 =6800 N/c towards q2 from A
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B) Field due to q1 is E1 = k*q1/x1^2 = (9*10^9*5.5*10^-9)/0.1^2 = 4950 N/C towards q1 from B
Field due to q2 is E2 = k*q2/x2^2 = (9*10^9*10*10^-9)/(0.35^2) = 735 N/C towards q2 form B
net electric field is E = E1+E2 = 4950+735 = 5685 N/c
C) Electric force on proton at A is FA = q*E = 1.6*10^-19*6800 = 1.08*10^-15 N/C towards q2 from A
D) on proton the direction of force is in the direction of field
hence the direction is from A towards q2
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