An oscillation can be described by the equation: times = 22.9 (cm) * cos(86.9(hz

Question

An oscillation can be described by the equation: times = 22.9 (cm) * cos(86.9(hz) * t(sec) + 82.6). Based on this equation, period of the oscillation in seconds? Consider an object oscillating on a spring if the oscillation is 2.33 seconds and the mass of the object is 0.3606 kilograms, what is the spring constant in N/m? If a hanging mass is 55/1 grams, what is the mass in kilograms? An oscillation can by the equation: times = 37.8(cm) * cos(35.4(hz) * t(sec) + 53.2. Based on this equation, what is the angular frequency of the oscillation in Hertz?

Explanation / Answer

given equation x = 22.9*cos(86.9t + 82.6)

equation of SHM x = A*cos(wt+phi)

amplitude A = 22.9 cm

angular frequency w = 2*pi*f = 86.9

phase difference phi = 82.6 rad

time period T = 1/f = w/(2pi) = 86.9/(2pi) = 13.8 s <<<<======ANSWER

==================================

Q 5)

time period T = 2*pi*sqrt(m/k)

2.33 = 2*pi*sqrt(0.3606/k)

K = 2.62

Q6)

1 kilogram = 1000 grams

1 gram = 0.001 kilograms

55.1 grams = 55.1*0.0001 = 0.0551

---------------

Q 7)

given equation x = 37.8*cos(35.4t + 53.2)

equation of SHM x = A*cos(wt+phi)

angular frequency w = 2*pi*f = 35.4

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.