Question 15 of 20 Map Sapling Learning macmillan learning An initially uncharged

Question

Question 15 of 20 Map Sapling Learning macmillan learning An initially uncharged air-filled capacitor is connected to a 4.07-V charging source. As a result, 6.77 x 105 C of charge is transfered from one of the capacitor's plates to the other. Then, while the capacitor remains connected to the charging source, a sheet of dielectric material is inserted between its plates, completely filling the space. The dielectric constant of this substance is 3.67. Find the capacitors potential difference and charge after the insertion. Potential difference after insertion of dielectric: Number Charge after insertion of dielectric: Number

Explanation / Answer

Here,

V = 4.07 V

Q = 6.77 *10^-5 C

k = 3.67

potential difference after insertion of dielectric

as the capacitor is stil connected to the source

potential difference after insertion of dielectric = 4.07 V

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for the charge

charge after insertion of dielectric = Q * k

charge after insertion of dielectric = 3.67 * 6.77 *10^-5

charge after insertion of dielectric = 2.484 *10^-4 C

the charge after insertion of dielectric is 2.484 *10^-4 C

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