a.What is the magnitude of the electric field at point P, located at (6.00 cm, 0

Question

a.What is the magnitude of the electric field at point P, located at (6.00 cm, 0), due to Q1 alone?

b.What is the x-component of the total electric field at P?

c.What is the y-component of the total electric field at P?

d.What is the magnitude of the total electric field at P?

e.Now let Q2 = Q1 = 2.30 C. Note that the problem now has a symmetry that you should exploit in your solution. What is the magnitude of the total electric field at P?

f.Given the symmetric situation of the previous problem, what is the magnitude of the force on an electron placed at point P?

Two charges, Q1= 2.30 C, and Q2= 5.90 C are located at points (0,-3.50 cm ) and (0,+3.50 cm), as shown in the figure.

Explanation / Answer

Charge Q1 = 2.30 C, Charge Q2 = 5.90 C, k = 9x109 N.m2/C2

a)electric field:

E = kQ1/(0.0352 + 0.0602) = 4.29*106 N/C

b) x-component of electric field:

Ex = kQ1 * 0.060/(0.0352 + 0.0602)3/2 + kQ2 * 0.060/(0.0352 + 0.0602)3/2

=1.32*107 N/C

c) y-component of electric field:

Ey = kQ1 * 0.035/(0.0352 + 0.0602)3/2 - kQ2 * 0.035/(0.0352 + 0.0602)3/2

= -3.38*106 N/C

d) magnitude of electric field:

E = [(1.32*107)2 + (-3.38*106)2] = 1.36*108 N/C

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