For part 3 of 3, options are same as part 1 options. Physics2 class need help un

Question

For part 3 of 3, options are same as part 1 options. Physics2 class need help understanding, thanks in advance.

001 (part 1 of 3) 10.0 points Consider 3 charges arranged as shown. 3.63 AC 1.23 m 8.3 ALC 2.46 m. 2.63 pC IV Find the direction of the resultant electric force on the -2.63 pwC charge at the origin due to the other two charges. The value of the Coulomb constant is 8.9875 x 109 N.m2/C2 1. Along the negative y-axis 2. Along the negative a-axis 3. In quadrant III 4. In quadrant II 5. Along the positive ar-axis 6. In quadrant I 7. In quadrant IV 8. Along the positive y-axis 002 (part 2 of 3) 10.0 points Determine the magnitude of the resultant electric force on the -2.63 pC charge at the origin due to the other two charges. Answer in units of N 003 (part 3 of 3) 10.0 points Determine the direction of the resultant elec- tric field on the -2.63 puC charge at the origin due to the other two charges.

Explanation / Answer

Field due to 3.63 uC at origin is E1 = k*Q1/r1^2 = (9*10^9*3.63*10^-6)/1.23^2 = 21594.3 N/C along -Y-axis

Field due to -8.3uC at origin is E2 = k*Q2/r2^2 = (9*10^9*8.3*10^-6)/(2.46^2) = 12343.84 N/C along -X-axis

so the answer for part 1) is In quadrant III

Net electric field at origin is E = sqrt(E1^2+E2^2) = sqrt(21594.3^2+12343.84^2) = 24873.4 N/C

part 2) Force on -2.63 uC is F = q*E = 2.63*10^-6*24873.4 = 0.06542 N

part 3) direction is theta = tan^(-1)(E1/E2) = tan^(-1)(21594.3/12343.84) = 60 .3 degrees below the -X-axis i.e III quadrant

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