The index of refraction of a calcite (CaCo_3) glass depends on the electric fiel
ID: 1524939 • Letter: T
Question
The index of refraction of a calcite (CaCo_3) glass depends on the electric field polarization (x-polarization or y-polarization). The equations for the two refractive indices versus wavelength (lambda_0 are) (lambda_0 in micrometers): n_x^2 - 1 = 0.8559 lambda_0^2/lambda_0^2 - 0.003457 + 0.8391 lambda_0^2/lambda_0^2 - 0.019881 + 0.0009 lambda_0^2/lambda_0^2 - 0.038809 + 0.6845 lambda_0^2/lambda_0^2 - 49.07003 n_y^2 - 1 = 1.0856 lambda_0^2/lambda_0^2 - 0.006236 + 0.0988 lambda_0^2/lambda_0^2 - 0.020164 + 0.317 lambda_0^2/lambda_0^2 - 131.515 For a 13mm thick (z dimension) piece of calcite glass, what is the difference in optical path length (optical path difference, or OPD) for the two orientations at 632.8 nm wavelength (HeNe laser in air)? What thickness is required to get a quarter wave difference (A0/4) for 1000nm wavelength of light between the x- and y-plarized rays?Explanation / Answer
a) optical path difference = 13/1.67
= 7.78 mm
b) thickness required = (1000/632.8) * 13
= 20.54 mm
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