em 5 (20 points). This problem is designed to evaluate your basic understanding

Question

em 5 (20 points). This problem is designed to evaluate your basic understanding of ohm's irchhoffs Voltage Law. Consider the circuit shown in Figure 4. R2 R1 1km 6800 4700 V 3 V Src Figure 4. Circuit with a voltage source and resistors 5,a (3 points): Use passive sign convention to assign the correct polarities to the voltages RI VR and Vas. Re-draw the circuit indicating these polarities. 5.b (3 points): Use Kirchhoff's voltage law to determine an expression for V re in terms of the voltages VRI, and V R3 s.c (3 points): use ohm's law to re-write your expression from 5.b in terms of the current and numerical resistor yaluesl 5-d (3 points): solve for the numerical value of the current se (3 points): solve for the numerical values of the voltages vez, and vex. Grading Rubric C 5.b (3 points): Correct expression for re in terms of the voltages Vau, V and Wes 5.c (3 points): Correct expression for V in terms of 1 and numerical resistor values 5 d (3 points): Correct numerical value of 5.e (3 points Correct numerical value of and V

Explanation / Answer

5.a) (-,+) (-,+) (-,+)

5.b)Vsrc = V(R1) + V(R2) + V(R3)

5.c)Since the same current flows through the resistors connected in series:

Vsrc = I R1 + I R2+ I R3 = I (R1 + R2 + R3)

5.d)3 = I (1000 + 680 + 470) => I = 3/2150 = 0.0014 A

Hence, I = 0.0014 A

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