Two point charges (q1 = -4.7?C and q2 = 8.4 ?C) are fixed along the x-axis, sepa

Question

Two point charges (q1 = -4.7?C and q2 = 8.4 ?C) are fixed along the x-axis, separated by a distance d = 8.1 cm. Point P is located at (x,y) = (d,d). h2_pointA Two point charges (q1 = -4.7?C and q2 = 8.4 ?C) are fixed along the x-axis, separated by a distance d = 8.1 cm. Point P is located at (x,y) = (d,d). 1) What is Ex(P), the value of the x-component of the electric field produced by q1 and q2 at point P? 2) What is Ey(P), the value of the y-component of the electric field produced by q1 and q2 at point P?

Explanation / Answer

Well, you know that E=F/q which eventually will get to kQ(source)/r^2

so by using this equation you simply plug in what is given. if i am not mistaken about the picture, P is right above q2 so that won't affect the x-component.

So, you will have Ex(P)=(9E9)*(-4.7E-6)/(.081^2+.081^2).
this will give you the magnitude of the electric field produced by q1. all thats left is to multiply your answer by a sin(45) and voila, there's your answer!
This should be your final answer (-3223593.96N/C)

for the second part you do the same, use the formula but this time q2 will affect it because you are looking for the y-component.

Ey(P)=(9E9)*(8.4E-6)/(.081^2) which equals out to 11522633.74 N/C.
to get the final answer just use the answer from part A and subtract it from the above answer and you are all set to go!
This should be the final answer for the second part. (11522633.74 N/C)

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