Three balls, with charges of +4 q , 2 q , and q , are equally spaced along a lin
ID: 1525194 • Letter: T
Question
Three balls, with charges of +4q, 2q, and q, are equally spaced along a line. The spacing between neighboring balls is r. We can arrange the balls in three different ways, as shown in the figure. In each case, the balls are in an isolated region of space very far from anything else.
(a) Rank the three cases, from largest to smallest, based on the magnitude of the net force experienced by the ball with the +4q charge. (Use only ">" or "=" symbols. Do not include any parentheses around the letters or symbols.)
+4g +4 II I II I II I +4 l I II I I I I I I II II I I I I I I I I I I I I I I I I I I I I I I I I I IExplanation / Answer
In case 1 and 3 the force due to the two charges -q and -2q are towards right
in case 2 the forces are opposite in direction
the net force is greater in case 1 , next case 3 and next case 2
a) 1 > 3 > 2-------------------------Answer
b)
the net force due to two charges on the charge 4q in case 1 is
F = k * 4q * 2q / r^2 + k * 4q * q / (2r)^2
F = 9 * k * q^2 / r^2
F = + 9 * 9 * 10^9 (5.5*10^-6)^2 / 0.45^2
F = + 12.1 N
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