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Electric Fields In this diagram, one of the two tiny interacting particles carri

ID: 1525403 • Letter: E

Question

Electric Fields In this diagram, one of the two tiny interacting particles carries three times as much charge as the other. Which particle, if either, experiences a bigger electric force? Explain how you know. Which particle, if either, feels a bigger electric field? Explain. Intuitively, what would you guess is the ratio of the electric field felt by Q to the electric field felt by 3Q? Reconcile your part C conclusion about the fields with your part A conclusion about the forces. In other words, explain intuitively how the particles can feel different fields but the same forces? Like what we did in the last post lab, three point charges of 2.00 mu C, 7.00 mu C, and -4.00 mu C are located at the corners of an equilateral triangle as shown at the right. Calculate the net electric field at the location of the 7.00-mu C charge. Using the result from part 1 (instead of Coulomb's law), calculate the net electric force on the 7.00-mu C charge.

Explanation / Answer

Q1. Electrostatic force experienced by both charges will be same and will be given by : K (Q)(3Q)/ d^2 ( where d is the distance between two particles.)

Q.2 Let's caculate the expression of electric field by small charge and big charge,

E ( for small charge) = K (3Q)/ ( d)^2

E( for large charge) = K(Q)/ d^2

the smaller particle will experience bigger field

Q.3 Ratio = K (3Q)/ ( d)^2 /  K(Q)/ d^2= 3:1

Q.4 Electric field due to a charge at any point is defined is at the force experienced by unit charge placed at that point, so it makes Electric field as a charateristic property, while electrostatic force is the mutal force between two chrages.

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