suppose the conducting spherical she in the figure below carries a charge of 3.2

Question

suppose the conducting spherical she in the figure below carries a charge of 3.20 nc and that a charge of -1.00 nC is at the center of the sphere. If a = 1.60 m and b = 2.40 m, find the electric field at the following. r = 1.50 m magnitude 0.44 Your response differs from the correct answer by more than 10%. Double check your calculations. N/C direction radially inward r = 2.20 m magnitude 0 N/C direction The magnitude is zero. r = 2.50 magnitude 2.2 Your response differs from the correct answer by more than 10%. Double check your calculations. N/C direction radially outward What is the charge distribution on the sphere? inner surface 0.031 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.nC 0.03 outer surface Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. nC

Explanation / Answer

step;1

Given data

charges q1=3.2nC

charges q2=-1 nC

inner radius of sphere a=1.6 m

outer radius of the sphere b=2.4 m

radius r =1.5 m

step;2

now we find the electric field in distance r=1.5 m

the electric field E=9*10^9*q1/r^2

                        =9*10^9*-1*10^-9/1.5^2=-4 N/c

step;3

now we find the electric field at r=2.5 m

the electric field E=9*10^9*(3.2-1)*10^-9/2.5^2=3.168 N/c

step;4

now we find the charge on the sphere

=>the charge on the inner surface of sphere is -1 nC because the charge q2 is lies centre to inner surface of the sphere

=>the charge on the outer surface of the sphere Q=3.2-1=2.2 nC

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