A scuba diver makes a slow descent into the depths of the ocean. His vertical po

Question

A scuba diver makes a slow descent into the depths of the ocean. His vertical position with respect to a boat on the surface changes several times. He makes the first stop 8.0 m from the boat but has a problem with equalizing the pressure, so he ascends 4.0 m and then continues descending for another 10.0 m to the second stop. From there, he ascends 2.0 m and then descends for 14.0 m, ascends again for 8.0 m and descends again for 11.0 m, where he makes a stop, waiting for his buddy. Assuming the positive direction up to the surface (+), express his net vertical displacement vector (in m) in terms of the unit vector . (Express your answer in vector form.)

What is his distance to the boat (in m)?

Explanation / Answer

Net vertical displacement D = +8 – 4 + 10 – 2 + 14 – 8 + 11

Simply Adding these vectors = 43 – 14

D = 29

Distance from Boat = 29 m

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