x CA 100.0-N Bird Feederis x MCA Block of Mass M s 6 x G Two forces are applied
ID: 1526337 • Letter: X
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x CA 100.0-N Bird Feederis x MCA Block of Mass M s 6 x G Two forces are applied ti x C A44 G Bullet Leaves The x M G br molecular mass Goo x L VA Assignment 4 C www.webassign ne 15467739 t/web/Student/Assignment-Responses/submit?dep 2. -13 points SerCP10 4.P. 012. My Notes Ask Your Teacher wo forces are applied to a car in an effort to move it, as shown in the figure below. (Let F1 415 N and F2 359 N. Assume up and to the right are in the positive directions.) I 30° (a) What is the resultant vector of these two forces? magnitude direction o to the right of the forward direction (b) If the car has a mass of 3,000 kg, what acceleration does it have Ignore friction. m/s Need Help? Read It 3. -13 points SerCP10 4.P. 019 My Notes Ask Your Teacher 1/30/2017Explanation / Answer
Given,
F1 = 415 N
F2 = 359 N
Fy = F1 * cos(10) + F2 * cos(30)
Fy = 415 * cos(10) + 359 * cos(30)
Fy = 719.6 N
Fx = F2 * sin(30) - F1 * sin(10)
Fx = 359 * sin(30) - 415 * sin(10)
Fx = 107.4 N
F = sqrt(Fx^2 + Fy^2)
F = sqrt(107.4^2 + 719.6^2)
F = 727.6 N
Direction, = tan^-1(107.4/719.6)
Direction, = 8.5o
(b)
m = 3000 kg
We know,
F = m*a
a = F/m = 727.6 / 3000
a = 0.243 m/s^2
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