Use the following values for mass and charge: an electron has mass me = 9.11×10-

Question

Use the following values for mass and charge: an electron has mass me = 9.11×10-31 kg and charge -e, a proton has mass mp = 1.67×10-27 kg and charge +e, an alpha particle has mass malpha = 6.65×10-27 kg and charge +2e, where e = 1.60×10-19 C. An electron is released from rest in a vacuum between two flat, parallel metal plates that are 9.0 cm apart and are maintained at a constant electric potential difference of 700 Volts. If the electron is released at the negative plate, what is its speed just before it strikes the positive plate?What is the kinetic energy of the electron in units of eV?

Explanation / Answer

the electric potential energy provides the kinetic energuy of motion:

q V = 1/2 m v^2

v = sqrt (2 q V/m)

v = sqrt (2 x 1.6 x 10^-19 x 700/(9.1 x 10^-31) = 1.57 x 10^7 m/s

Hence, v = 1.57 x 10^7 m/s

KE = 1/2 m v^2

KE = 0.5 x 9.1 x 10^-31 x (1.57 x 10^7)^2 = 1.12 x 10^-16 J = 1.12 x 10^-16 x 1.6 x 10^-19 eV = 699 eV

Hence, KE = 699.1 eV

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