a. Calculate the root-mean-square distance a perfume molecule moves along a part

Question

a. Calculate the root-mean-square distance a perfume molecule moves along a particular direction though the air in one second, given a diffusion constant of 1.21 × 10-6 m2/s.

b. When your friend across the room opens a bottle of perfume, the scent reaches your nose in a matter of seconds. You notice the smell of the perfume so soon after the bottle is opened because ____________________. (choose one from the list below)

- the perfume molecules were heaviner than the surrounding air.

- the perfume molecules diffused quickly across the room.

- there were more perfume molecules than air molecules in the room.

- air currents moved perfume molecules across the room.

Explanation / Answer

a)We know that,

t = L^2/D

where, L is the length and D is the diffusion constant

L^2 = t x D

L = sqrt (t x D) = sqrt (1 x 1.21 x 10^-6) = 1.1 x 10^-3 m

Hence, L = 1.1 x 10^-3 m

b)the perfume molecules diffused quickly across the room.

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