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Explanation / Answer

Given

   nuclei thorium 234 Th 90 and 4He2

of charges q1 = 90*1.6*10^-19 C, q2 = 2*1.6*10^-19 C

separated by a distance is r= 13*10^-15 m

from coulomb's law

   the force between two charges is F = kQ1*Q2/r^2

  
      
       F = 9*10^9 *90*1.6*10^-19*2*1.6*10^-19/(13*10^-15)^2
      

       F = 245.4 N

fromm

   Newton's second law of motion

   F = ma
   a = F/m
   = 245.4/(6.64*10^-27) m/s2
   =3.69578*10^28 m/s2

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