A constant electric field of magnitude E = 575 V/m points in the positive x-dire

Question

A constant electric field of magnitude E = 575 V/m points in the positive x-direction. A charge Q is moved in positive x-direction within the field by an external force. The sign of the work depends on the sign of the charge. Incorrect The work required is independent of the angle of the path with respect to the field. Incorrect Without an external force, a free negative charge would accelerate perpendicular to the depicted path. Incorrect The work required is proportional to the square of the charge. Incorrect No work is required. How much work by an external force does it take to move the charge Q = 23 mu C from x_1 = 0.02 m to x_2 = 0.43 m?

Explanation / Answer

Work is force x displacement in the direction of force.

Force on cahrge Q is EQ = 575 *23 x 10-6 = 0.013225 N.

Displacement in the (x) direction of force is 0.43m - 0.02 = 0.41m

Work = 0.013225 * 0.41=5.4225x10-3J

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