Electric Field due to Two Point Charges-MC Two point charges are placed on the x

Question

Electric Field due to Two Point Charges-MC Two point charges are placed on the x axis The first charge, Q_1 = 8.5 nC, is placed a distance.x_1 = 13m from the origin along the positive x axis; the second charge, Q_2 = 3.5 nC, is placed a distance x_2 = 9.0m from the origin along the negative x axis Now, assume that charge Q_2 is negative; Q_2 = -3.5 nC What is the net electric field at the origin point O? Give the x and y components of the electric field as an ordered pair. Express your answer in newtons per coulomb to three significant figures. Keep in mind that an x component that points to the right is positive and a y component that points upward is positive.

Explanation / Answer

part B

E1x = -k*Q1/x1^2 = -9*10^9*8.5*10^-9/13^2 = -0.453 N/C

E2x = - k*Q2/x2^2 = -9*10^9*3.5*10^-9/9^2 = -0.389 N/C

Eox = E1x + E2x = -0.453 - 0.389 = -0.842 N/C

Eoy = 0

Eox , Eoy = -0.842 , 0

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