A charge of 2.65 C is held fixed at the origin. A second charge of 2.65 C is rel

Question

A charge of 2.65 C is held fixed at the origin. A second charge of 2.65 C is released from rest at the position (1.25 m, 0.570 m).

Part A If the mass of the second charge is 2.25 g , what is its speed when it moves infinitely far from the origin?

v = ______ m/s

Part B At what distance from the origin does the second charge attain half the speed it will have at infinity?

r = ______ m

Problem 20.34 A charge of 2.65 uC is held fixed at the origin. A second charge of 2.65 AC is released from rest at the position (1.25 m, 0.570 m). Part A the mass of the second charge is 2.25 g what is its speed when it moves infinitely far from the origin 5.45 In/S Submit My Answers Give U incorrect; One attempt remaining; Try Again Part B At what distance from the origin does the second charge attain half the speed it will have at infinity? 2.5 Submit My Answers Give U Incorrect, Try Again; 3 attempts remaining

Explanation / Answer

at givem position,

distance between the charges,

r= sqrt(1.25^2 + 0.570^2) = 1.374 m

at this location, Electric PE of system = k q1 q2 / r

= (9 x 10^9) (2.65 x 10^-6)^2 / (1.374)

= 0.046 J

KE = 0

when they are very far apart,

PE = 0

Applying energy conservation ,

PEi + KEi = PEf + KEf

0.046 + 0 = 0 + ( 2.25 x 10^-3 x v^2 / 2)

v = 6.39 m/s

(B) when v = v/2

then KE = 0.0115 J

then Pe at thislocation = 0.046 - 0.015 = 0.0345 J

Pe = k q1 q2 / r

0.0345 = (9 x 10^9) (2.65 x 10^-6)^2 / r

r = 1.83 m

  

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