You are watching an archery tournament when you start wondering how fast an arro

Question

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. You find the arrow stuck in the ground 66.0 m away, making a 2.3 angle with the ground. What was the landing speed of the arrow?

I already found the amount of time the arrow was in the air for: 0.52 s and how fast the arrow was shot: 127 m/s. I tried finding the velocity by the equation v = -gt and got -5.096, but this was marked wrong.

Explanation / Answer

Here, for time of light , t = 0.52 s

initial speed , u = 127 m/s

Now, vertical speed , v = - g * t = - 5.096 m/s

for the landing speed

landing speed = sqrt(v^2 + u^2)

landing speed = sqrt(127^2 + 5.096^2)

landing speed = 127.1 m/s

the landing speed of arrow is 127.1 m/s

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