We can\'t use the Digital Multimeter to measure the voltage on the capacitor dur

Question

We can't use the Digital Multimeter to measure the voltage on the capacitor during the tab experiment because: only a small current range could be measured of the high internal resistance of the Multimeter only a small voltage range could be measured of the low internal resistance of the Multimeter Suppose after charging a 6.3 mu F capacitor to 10 V, you connect it to the second uncharged capacitor of 2.6 mu F What voltage will your voltmeter read across the second capacitor after repeating the charge sharing process two times?

Explanation / Answer

let

C1 = 6.3 micro F

C2 = 2.6 micro F

V = 10 V

initial charge on C1, q1 = C1*V

= 6.3*10

= 63 micro C

when C1 is connected to C2,

Cnet = C1 + C2

= 6.3 + 2.6

= 8.9 micro C

so, the charge 63 micro C is shared by the two capacitors.

voltage across the capacitors,

V2 = q1/Cnet

= 63/8.9

= 7.08 volts

charge on C2, q2 = C2*V2

= 2.6*7.08

= 18.4 micro C

when C1 is charged and connected to C2

charge on both capacitors, Q = q1 + q2

= 63 + 18.4

= 81.4 volts

voltage across C2, V2 = Q/Cnet

= 81.4/8.9

= 9.15 volts <<<<<<<<<-------------------Answer

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