Halliday, Fundamentals of Physics, 10e LUS Help I System Announcements Unread) C

Question

Halliday, Fundamentals of Physics, 10e LUS Help I System Announcements Unread) Chapter 04, Problem og9 In the figure, a lump of wet putty moves in uniformo circular motion as it rides at a radius of 29.0 am on the rim of a wheel rotating counterclockwise with a period of 3.50 ms. The lump then happens to fly off the rim at the 5 o'clock position (a distance d 2.50 m from a wall. At what height on the wall does the lump hit? 1.40 m from the floor and at a Purry the tolerance is +/-2% Click if you would like to show work for this question Open Show Work LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM I R2000:201Zlohn wiley ASons Inc. All Rights Reserved. A Division of lobo Wiley asons, Inc. Version 4.22.1.2

Explanation / Answer

PROJECTILE

along horizontal

initial velocity vox = vo*costheta

ax = 0

from equation of motion

x-Xo = vox*T+ 0.5*ax*T^2

x-X0 = vo*costheta*T

T = (x-X0)/(vo*costheta)......(1)

along vertical

voy = vo*sintheta

acceleration ay = -g

from equation of motion

y-y0 = voy*T + 0.5*ay*T^2

y-y0 = (vo*sintheta*(x-x0))/(vo*costhetra) + (0.5*ay*(x-x0)^2)/(vo^2*(costheta)^2)

y-y0 = (x-X0)*tantheta + ((0.5*ay*(x-X0)^2)/(vo^2*(costheta)^2))

y0 = 1.4 m

y = ? m

x-xo = 2.5 m

theta = 30

speed v0 = r*w = r*2pi/T = 0.29*2*pi/(3.5*10^-3) = 520.6 m/s

y-1.4 = (2.5*tan30) - ((0.5*9.8*2.5^2)/(520.6^2*(cos30)^2))

y = 2.84 m <<<------------answer

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