Model rocket is launched straight upward with an initial speed of 53.0 m/s. acce

Question

Model rocket is launched straight upward with an initial speed of 53.0 m/s. accelerates with a constant upward acceleration of 1.50 m/s^2 until its genes stop at an altitude of 130 m. What can you say about the motion of the rocket after its engines stop? What is the maximum height reached by the rocket? Your response differs from the correct answer by more than 10%. Double check your calculations. m How long after liftoff does the rocket reach its maximum height? Your response differs from the correct answer by more than 10%. Double check your calculations. s How long is the rocket in the air? Your response differs from the correct answer by more than 10%. Double check your calculations. s

Explanation / Answer

when the engine stops

speed

v1^2 - v0^2 = 2*a*y

v1^2 -53^2 = 2*1.5*130

v1^2 = 3199 m

height reached after engine stops h = v1^2/2g = 3199/20 = 159.95 m

maximm height = 130 + 159.95 = 289.95 m

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(c)

y = v0*t + (1/2)*a*t^2

130 = (53*t) + (1/2)*1.5*t^2

t = 2.37 s

t1 = v1/g = sqrt(3199)/10 = 5.65 s

total time = t+t1 = 6.02 s

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(d)

time taken tot reach grond t2 = sqrt(2*H/g) = sqrt(2*289.95/9.8) = 7.7 s

time = t + t1 + t2 = 13.72 s <<-----------answer

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