A cameraman on a pickup truck is traveling westward at 25 km/h while he videotap

Question

A cameraman on a pickup truck is traveling westward at 25 km/h while he videotapes a cheetah that is moving westward 30 km/h faster than the truck. Suddenly, the cheetah stops, turns, and then run at 45 km/h eastward, as measured by a suddenly nervous crew member who stands alongside the cheetah's path. The change in the animal's velocity takes 2.3 s. What are the (a) magnitude and (b) direction of the animal’s acceleration according to the cameraman and the (c) magnitude and (d) direction according to the nervous crew member?

Explanation / Answer

according to cameraman,

initial velocity = 30 km/h (westward)

final velocity = 25 + 45 = 70 km/h (eastward)

accealaration = dv/dt = (70 - (-30))/2.3 = 100/2.3 km/hs = 100 x 1000/(3600 x 2.3) m/s2 = 1000/(36 x 2.3) = 12.0773 m/s2 eastward

a) 12.0773 m/s2

b) eastward

According to crew member,

initial velocity = 30 + 25 = 55 km/h (westward)

final velocity = 45 km/h (eastward)

accealaration = dv/dt = (45 - (-55))/2.3 = 100/2.3 km/hs = 100 x 1000/(3600 x 2.3) m/s2 = 1000/(36 x 2.3) = 12.0773 m/s2 eastward

a) 12.0773 m/s2

b) eastward

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.