You are flying really fast over the surface of the Earth at constant speed of 0.

Question

You are flying really fast over the surface of the Earth at constant speed of 0.75c. You see two synchronized clocks are on points X and Y. They are synchronized in the earth surface reference frame. As you pass over the clock at X, both your stopwatch and the clock at X read t = 0. As soon as you pass the clock at X, are clocks X or Y slower or faster than yours ? Compare all three clocks, yours, X and Y. Point Y is further away from X and you are moving toward Y after passing X. When you pass over Y, does the clock Y shows the same time, earlier or later time? Discuss answer (a) and (b). Are they consistent or contradictory? Give a brief explanation for either case.

Explanation / Answer

when a body moves with a relativistic speed, it will slow down as compare to real time.

a) since clocks X and Y are based in earth, they would be faster than your clock.

b) Clock Y will show a later time owing to the fact that it's far from clock X

c) Both the results are consistent.

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