What does the balance read when the elevator is ascending with a constant speed

Question

What does the balance read when the elevator is ascending with a constant speed of 32 m/s? N What does the balance read when the elevator is descending with a constant speed of 26 m/s? N What does the balance read when the elevator is ascending at 32 m/s and gaining speed at a rate of 8 m/s2? N Suppose that from t = 0 to t = 4.7 s, the elevator ascends at a constant speed of 10 m/s. Its speed is then steadily reduced to zero during the next 3.8 s, so that it is at rest at t = 8.5 s. Describe the reading of the scale during the interval 0

Explanation / Answer

constant speed implies zero acceleration.

Wa = mg = 2 x 9.8 = 19.6 N

W = 19.6 N

b)Wb = 19.6 N

c) a = 8 m/s^2

Wc = m (g - a) = 2 (9.8 - 8) = 3.6 N

Wc = 3.6 N

d) a = 10/4.7 = 2.13 m/s^2

Wd = 2 (9.8 - 2.13) = 15.34 N

Wd = 15.34

a' = 10/(8.5 - 3.8) = -2.13 m/s^2

its retardation since the elevator stops

wd' = 2 (9.8 - (-2.13) = 23.86 N

Wd' = 23.86 N

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