Xo= -7.49 x 10^-6m. Find the magnitude and direction of the electric field at x
ID: 1530702 • Letter: X
Question
Xo= -7.49 x 10^-6m. Find the magnitude and direction of the electric field at x = 9.73 x 10^-6 m on the x axis due to this electron.Search Q&A; Chegg con 2/10/2017 10:00 AM A 7.6l20 Gradebook Print calculator Periodic Table Question 1 of 15 Incorrect Incorect Sapling Learning learniirig An electron is located on the x axis at xo 7.49 x 10 m. Find the magnitude and direction of the electric field at x 9.73 x 106 m on the x axis due to this electron. Magnitude: Number 48.56 x 10 NIC Direction: O Positive x direction Negative x direction O Neither of these im Check Answer o Next Exil
Explanation / Answer
field due to a point charge is E = k*q/d^2
E = (9*10^9*1.6*10^-19)/((9.73+7.49)*10^-6)^2
E =4.85 N/C or V/m
direction is along the Negative X-direction
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