Venus 108 mil km 72 AU 0.75 Earth Mar Distance from Sun in km Distance from Sun

Question

Venus 108 mil km 72 AU 0.75 Earth Mar Distance from Sun in km Distance from Sun in AU Albedo 150 mil kmm 1 AU227 mil km 0.31 1.51 AU 0.16 Energy reaching orbit of planet. Use inverse square rule to calculate solar flux (S) at planet's distance: Splanet-Sreference (distancereference /distanceplanet) S 1366 W/m2 Use Earth's values as the references Taking into account spherical shape Divide the above by 4 (due to spherical shape of planet). This is the incoming radiation at the top of the atmosphere Every planet will reflect some energy Multiply the above by (1-Albedo). This is the radiation available to warm the surface. If we know energy received we can calculate temperature. Insert above as E into Stefan-Boltzman equation solving for temperature: where -0.000000057 w/m2/K4 Temperature in Celcius. Convert above from K to °C, where " -273 This is the temperature of the surface without a Greenhouse effect

Explanation / Answer

Flux,S drops off with increasing dstance by =1/r2

or, S inversely proportional to r(radial distance from star)

distance from sun(km)

Diff(venus) =462-32=430 C

diff(earth) =15+66 =81C

diff(mars)= -55+130= 75C

venus earth mars

distance from sun(km)

108 mil km 150 227 distance from sun(AU) .72 1 1.51 Albedo 0.75 0.31 0.16 energy reaching orbit of planet 1366*1/.722=2635 1366 1366*1/1.512=599 taking into account the shape 658.75 341.5 149,75 reflection by albedo 658.75*.75=494 105.86 149.75*.16=23.96 temp(sigma=0.000000057) k 4th root(494/sigma)=305K 207K 143K c=k-273 32 -66 -130

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