(6%) Problem 5: Consider the parallel-plate capacitor shown in the figure. The p

Question

(6%) Problem 5: Consider the parallel-plate capacitor shown in the figure. The plate separation is 6.2 mm and the the electric field inside is 18N/C. An electron is positioned halfway between the plates and is given some initial velocity, Randomized Variables d 6.2 mm E 18 NC 50% Part (a) What speed, in meters per second, must the electron have in order to make it to the negatively charged plate? 50% Part (b) If the electron has half the speed needed to reach the negative plate, it will turn around and go towards the positive plate. What will its speed be, in meters per second, when it reaches the positive plate in this case? Grade Summary cotan0 asin() acotan0 cosho tanho cotanho ODegrees O Radians Hints: for a deduction. Hints remaining Feedback: deduction par feedback. -Use conservation of energy again using a different set offinal and Submission History Hints Use conservation of energy again, using a different set of final and initial conditions. 210100 6261000 40100 Totals

Explanation / Answer

Goven d= 6.2 mm ; E= 18N/c 1)Ee = ma . a=Ee/m =18×1.6×10-1/ 9.1× 1-31   = 3.16× 1012 m/sec2  . v 2 = 2as =2×3.1×10-12×3.1×10-3 : v= 14×104 m/ sec ; 2) v2 = 2as = 2× 3.16×1012 ×6.2 ×10-3   v= 19.7 × 104m/sec

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