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Question

ome File Edit View History Bookmarks People Window Help secure entrance 18partid-part08a Attempt 1 of 1 Your answer is partially correct. A particie moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (4.10 m, 440 m) with a velocity of -7.20 7 m/s and an acceleration of 13.7 msa. what are the (a) x and db) y of the center of the circular path? (a) N emberi Unit (b) SCORE Maximum Point Potential: 1.0 copyright 2000-2012 by John wiiey Sons, inc. er reiated companies. Airights reserved. Q W E R T Y U

Explanation / Answer

x= 4.10 m
y < 4.40 m
y = 4.40 m - radius

Fcent = -m * a

Also Fcent = m * w^2 * R

-m *a = m * w^2 * R

-a = w^2 * R

We now that w = v/r

-a = (v/r)^2 * R
-a = v^2 / R

R = v^2 / -a

R = (7.2 m/s)^2 / -(13.5 m/s^2)

R = 38.34 m

So x=4.10 m

y = 4.40m-R = 4.40 m - 38.3 m

y = -33.9m

coordinates (4.10 m, 38.9 m)

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