Two identical gold balls are 5 meters apart from each other. The volume of the b

Question

Two identical gold balls are 5 meters apart from each other. The volume of the balls is 1 cm3. Suppose someone can move one electron from each atom of ball A and give it to ball B.

1.What is the magnitude of the electrostatic force between two gold balls? (in units of N) Submit Answer Tries 0/4

2.What is the magnitude of the gravitional force between two gold balls? (in units of N) Submit Answer Tries 0/4

3.How many electrons would need to be transferred in order to balance these two forces? (electrons)

Explanation / Answer

1.)

q = charge on each ball = charge on one electron = 1.6 x 10-19 C

r = distance between the balls = 5 m

electrostatic force of attaraction is given as

F = k q2/r2

F = (9 x 109) (1.6 x 10-19)2 /52

F = 9.216 x 10-30 N

2)

V = volume of each ball = 1 cm3 = 1 x 10-6 m3

m = mass of each ball = density of gold x volume of each ball = 19320 x 10-6

gravitational force is given as

F = G m2/r2

F = (6.67 x 10-11) (19320 x 10-6)2 /52

F = 9.96 x 10-16 N

3.

let the charge be "Q"

for the equilibrium of forces

k Q2/r2 = 9.96 x 10-16

(9 x 109) Q2 /52 = 9.96 x 10-16

Q = 1.66 x 10-12

n = number of electrons = Q/e = (1.66 x 10-12)/(1.6 x 10-19) = 1.0375 x 107

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