The surface charge density on the outer shell is Answer: a. +1.9 times 10^-8 C/m

Question

The surface charge density on the outer shell is Answer: a. +1.9 times 10^-8 C/m^2. b. -4.57 times 10^-8 C/m^2. c. +5.51 times 10^-8 C/m^2. d. +8.55 times 10^-8 C/m^2. e +2.58 times 10^-8 C/m^2. The magnitude and direction of the electric field at 46.4 m from the center is answer: a. 1.00 times10^3 V/m, radially inward. b. 2.58 times 10^3 V/m, radially inward. c. 3.42 times 10^3 V/m, radially inward. d. 6.76 times 10^3 V/m, radially inward. e. 7.54 times 10^3 V/m, radially inward. -41.5 times 10^-3 C of charge is uniformly distributed throughout a spherical volume of 350 cm radius. How much charge is contained in a region of radius 324 cm from the center of the charge distribution? a. -32.9 mC. b. -58.5 mC. c. -75.2 mC. d. -85.0 mC. e. -92.0 mC. A charge of +700 C is uniformly distributed on a thin glass rod 100 cm long. See the figure at the right. Determine the electric field at P(0.00, + 3.60 cm) If I can follow what you are doing I will give partial credit. If I can't then, you get zero.

Explanation / Answer

for question 5 and 10 full question is not provided ,so i am answering only

Volume charge density is given by

sigma = Q/(4/3)piR3

So charge is directly proportional to cube of the charge

Q2/Q1 = (R2/R1)3

Q2=(-41.5 mC)(324/350)3 =-32.9 mC

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